Consider the following reactions: {({C7H14})}{{'A'}} {{ozonolysis}} {'B'} + {'C'}

A has molecular formula $\ce{C7H14}$ (MW = 98), which means DoU = 1 (one double bond). Ozonolysis gives B + C. The tests applied to B and C are:

• B gives iodoform test (positive) → B contains $\ce{-CO-CH3}$ group (methyl ketone or acetaldehyde)
• C gives silver mirror test (positive) → C is an aldehyde

Step 2: Identify B and C From the reactions shown:

• B gives iodoform → B is a methyl ketone: $\ce{CH3-CO-R}$
• C gives silver mirror → C is an aldehyde: $\ce{R'-CHO}$

For $\ce{C7H14}$ with 1 double bond: B + C must together have 7 carbons. This is 3-methylhex-3-ene → molecular formula $\ce{C7H14}$ ✓

Answer: Option (d)

Key Points to Remember:

• Iodoform test: detects $\ce{CH3CO-}$ group (methyl ketones + ethanal)
• Silver mirror test: detects aldehydes ($\ce{-CHO}$)
• Reconstruct alkene by replacing $\ce{C=O}$ of both fragments with $\ce{C=C}$