The number of optically active products obtained from the complete ozonolysis of the given compound is:
Hydrocarbons · Class 11 · JEE Main Previous Year Question
The number of optically active products obtained from the complete ozonolysis of the given compound is:
- a
- b✓
- c
- d
Ozonolysis followed by reductive workup () cleaves each double bond oxidatively, replacing it with carbonyl () groups.
None of the ozonolysis products contain a chiral center. Therefore, the number of optically active products = 0.
Key Points to Remember:
- Ozonolysis cleaves bonds, converting to
- A product is optically active only if it contains a chiral center
- Ozonolysis in presence of Zn or Dimethyl sulphide is called reductive ozonolysis, it prevents further oxidation of aldehydes produced during ozonolysis.
Practice this question with progress tracking
Want timed practice with adaptive difficulty? Solve this question (and hundreds more from Hydrocarbons) inside The Crucible, our adaptive practice platform.
More JEE Main Hydrocarbons PYQs
Identify product [A], [B] and [C] in the following reaction sequence:
Consider the given chemical reaction: Product "A" is:
A hydrocarbon 'X' with formula C6H8 uses two moles of H2 on catalytic hydrogenation of its one mole. On ozonolysis, 'X' yields two moles of methane dicarbaldehyde (malonaldehyde). The hydrocarbon 'X'…
The two products formed in above reaction are:
Consider the following reactions: {({C7H14})}{{'A'}} {{ozonolysis}} {'B'} + {'C'}