JEE Main · 2019 · Shift-IIeasySOL-011

The amount of sugar (C12H22O11) required to prepare 2 L of its 0.1 M aqueous solution is:

Solutions · Class 12 · JEE Main Previous Year Question

Question

The amount of sugar (C12H22O11\mathrm{C_{12}H_{22}O_{11}}) required to prepare 2 L of its 0.1 M aqueous solution is:

Options
  1. a

    17.1 g

  2. b

    136.8 g

  3. c

    68.4 g

    ✓
  4. d

    34.2 g

Correct Answerc

68.4 g

Detailed Solution

Strategy:\n> Use the formula: Mass =M⋅V⋅Mw= M \cdot V \cdot M_w. Find the molar mass of sucrose (sugar) first.\n\nStep 1: Molar mass of sugar (\ceC12H22O11\ce{C12H22O11})\nMw=12(12)+22(1)+11(16)=144+22+176=342textg/molM_w = 12(12) + 22(1) + 11(16) = 144 + 22 + 176 = 342\\text{ g/mol}.\n\nStep 2: Calculate mass\n- M=0.1textmol/LM = 0.1\\text{ mol/L}\n- V=2textLV = 2\\text{ L}\ntextMass=0.1times2times342=68.4textg\\text{Mass} = 0.1 \\times 2 \\times 342 = 68.4\\text{ g}\n\ntextAnswer:(3)\boxed{\\text{Answer: (3)}}

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