JEE Main · 2019 · Shift-IeasyATOM-009

The isoelectronic set of ions is:

Structure of Atom · Class 11 · JEE Main Previous Year Question

Question

The isoelectronic set of ions is:

Options
  1. a

    F,Li+,Na+\mathrm{F^-, Li^+, Na^+} and Mg2+\mathrm{Mg^{2+}}

  2. b

    N3,Li+,Mg2+\mathrm{N^{3-}, Li^+, Mg^{2+}} and O2\mathrm{O^{2-}}

  3. c

    N3,O2,F\mathrm{N^{3-}, O^{2-}, F^-} and Na+\mathrm{Na^+}

  4. d

    Li+,Na+,O2\mathrm{Li^+, Na^+, O^{2-}} and F\mathrm{F^-}

Correct Answerc

N3,O2,F\mathrm{N^{3-}, O^{2-}, F^-} and Na+\mathrm{Na^+}

Detailed Solution

🧠 The Multi-Ion Match We need a set where every single ion has the exact same electron count. This usually involves checking elements across periods 2 and 3 that have reached the 1s22s22p61s^2 2s^2 2p^6 configuration.

🗺️ The Electronic Audit Checking Option (c):

  • \ceN3\ce{N^3-}: 7+3=10 e7 + 3 = 10 \text{ e}^-
  • \ceO2\ce{O^2-}: 8+2=10 e8 + 2 = 10 \text{ e}^-
  • \ceF\ce{F^-}: 9+1=10 e9 + 1 = 10 \text{ e}^-
  • \ceNa+\ce{Na^+}: 111=10 e11 - 1 = 10 \text{ e}^- All members have 10 electrons, making them isoelectronic.

The Lithium Filter Notice options (a), (b), and (d) all contain \ceLi+\ce{Li^+}. Helium's electronic configuration is 1s21s^2 (2 e2 \text{ e}^-), while Neon's is 1s22s22p61s^2 2s^2 2p^6 (10 e10 \text{ e}^-). Since \ceLi+\ce{Li^+} (2 e2 \text{ e}^-) is present alongside species like \ceNa+\ce{Na^+} or \ceMg2+\ce{Mg^2+} (10 e10 \text{ e}^-), these options crash immediately.

⚠️ Common Traps Don't let the similar atomic numbers of \ceLi\ce{Li} (Z=3Z=3) and \ceNa\ce{Na} (Z=11Z=11) fool you into thinking their ions are isoelectronic. They are in the same group, but their ions fall back to different Noble Gas cores.

Answer: (c)\boxed{\text{Answer: (c)}}

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