JEE Main · 2025 · Shift-IhardBOND-175

Among SO2, NF3, NH3, XeF2, ClF3 and SF4, the hybridization of the molecule with non-zero dipole moment and highest…

Chemical Bonding · Class 11 · JEE Main Previous Year Question

Question

Among \ceSO2\ce{SO2}, \ceNF3\ce{NF3}, \ceNH3\ce{NH3}, \ceXeF2\ce{XeF2}, \ceClF3\ce{ClF3} and \ceSF4\ce{SF4}, the hybridization of the molecule with non-zero dipole moment and highest number of lone pairs of electrons on the central atom is:

Options
  1. a

    sp3sp^3

  2. b

    dsp2dsp^2

  3. c

    sp3d2sp^3 d^2

  4. d

    sp3dsp^3 d

Correct Answerd

sp3dsp^3 d

Detailed Solution

🧠 Find the species with non-zero dipole moment and the highest number of lone pairs on the central atom, then give its hybridization.

🗺️ Step 1 — Lone pairs and dipole moments:

| Molecule | Shape | LP on central atom | Dipole moment | |----------|-------|-------------------|--------------| | \ceSO2\ce{SO2} | Bent | 1 | ≠ 0 ✓ | | \ceNF3\ce{NF3} | Pyramidal | 1 | ≠ 0 ✓ | | \ceNH3\ce{NH3} | Pyramidal | 1 | ≠ 0 ✓ | | \ceXeF2\ce{XeF2} | Linear | 3 | = 0 ✗ | | \ceClF3\ce{ClF3} | T-shaped | 2 | ≠ 0 ✓ | | \ceSF4\ce{SF4} | See-saw | 1 | ≠ 0 ✓ |

Step 2 — Among polar molecules, highest LP on central:

\ceClF3\ce{ClF3}: 2 lone pairs on Cl → highest LP among polar molecules

Step 3 — Hybridization of \ceClF3\ce{ClF3}:

Cl: 3 bonds + 2 LP = 5 electron pairs → sp3dsp^3d hybridization

Answer: sp3d\boxed{\text{Answer: } sp^3d}

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