Match the LIST-I with LIST-II. | LIST-I (Molecule/ion) | LIST-II (Bond pair : lone pair on central atom) | |---|---| |…
Chemical Bonding · Class 11 · JEE Main Previous Year Question
Match the LIST-I with LIST-II. | LIST-I (Molecule/ion) | LIST-II (Bond pair : lone pair on central atom) | |---|---| | A. | I. 4 : 2 | | B. | II. 4 : 1 | | C. | III. 2 : 3 | | D. | IV. 2 : 2 |
Choose the correct answer from the options given below:
- a
A-IV, B-III, C-II, D-I
- b✓
A-III, B-IV, C-II, D-I
- c
A-III, B-IV, C-I, D-II
- d
A-II, B-I, C-IV, D-III
A-III, B-IV, C-II, D-I
🧠 Count bond pairs and lone pairs on the central atom for each species (using total bond pairs, including π-bond contributions).
🗺️ A. : I has 2 bonds + 3 LP → 2 : 3 → (III) ✓
B. : O has 2 bonds + 2 LP → 2 : 2 → (IV) ✓
C. : S forms 2 S–O bonds (one double, one single) counting all bond pairs:
- 1 S=O: contributes 2 bond pairs (σ + π)
- 1 S–O: contributes 1 bond pair
- 1 LP on S
- Total bond pairs = 3 + 1? Using full count: S effectively has 4 bond pairs (double bond = 2 pairs) + 1 LP → 4 : 1 → (II) ✓
D. : Xe has 4 bonds + 2 LP → 4 : 2 → (I) ✓
Matching: A–III, B–IV, C–II, D–I
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