JEE Main · 2019easyCORD-073

The compound that inhibits the growth of tumors is:

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

The compound that inhibits the growth of tumors is:

Options
  1. a

    trans-[Pt(Cl)2(NH3)2][\mathrm{Pt(Cl)_2(NH_3)_2}]

  2. b

    cis-[Pt(Cl)2(NH3)2][\mathrm{Pt(Cl)_2(NH_3)_2}]

  3. c

    cis-[Pd(Cl)2(NH3)2][\mathrm{Pd(Cl)_2(NH_3)_2}]

  4. d

    trans-[Pd(Cl)2(NH3)2][\mathrm{Pd(Cl)_2(NH_3)_2}]

Correct Answerb

cis-[Pt(Cl)2(NH3)2][\mathrm{Pt(Cl)_2(NH_3)_2}]

Detailed Solution

🧠 The cis-Platin Anchor

The drug that inhibits tumour growth is cis-platin, the cis isomer of [Pt(NH3)2Cl2][\mathrm{Pt(NH_3)_2Cl_2}].

Two structural facts make it active:

  1. cis geometry — the two Cl ligands are 90° apart, allowing both to leave and bind to adjacent N atoms on DNA.
  2. Pt(II) centre — kinetically slow, so the complex survives in the bloodstream long enough to reach tumour cells.

The trans isomer is biologically inactive (the two Cls are 180° apart and cannot bind adjacent DNA bases). Pd analogues are too labile (Pd-Cl exchange is fast) → no useful pharmacology.

🗺️ Eliminate Each Wrong Option

  • (1) trans-[Pt(Cl)2(NH3)2][\mathrm{Pt(Cl)_2(NH_3)_2}] — wrong geometry; cannot crosslink DNA. ✗
  • (2) cis-[Pt(Cl)2(NH3)2][\mathrm{Pt(Cl)_2(NH_3)_2}]cis-platin, the antitumour drug. ✓
  • (3) cis-[Pd(Cl)2(NH3)2][\mathrm{Pd(Cl)_2(NH_3)_2}] — too labile, hydrolyses before reaching the tumour. ✗
  • (4) trans-[Pd(Cl)2(NH3)2][\mathrm{Pd(Cl)_2(NH_3)_2}] — wrong on both counts. ✗

The "Pt + cis = Drug" Mnemonic

Three flags must align: Pt (slow kinetics), cis (geometry for DNA crosslinking), square-planar Pt(II) (correct geometry). Miss any one → not antitumour.

⚠️ Don't Confuse Pt and Pd

Both are group-10 d⁸ metals with similar electron count, but Pd–L bond exchange is ~10⁵ times faster than Pt–L. Pd can't survive in bloodstream long enough to act as a drug.

Answer: (2) cis-[Pt(Cl)2(NH3)2]\boxed{\text{Answer: (2) cis-}[\mathrm{Pt(Cl)_2(NH_3)_2}]}

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