JEE Main · 2019easyCORD-077

Wilkinson catalyst is:

Coordination Compounds · Class 12 · JEE Main Previous Year Question

Question

Wilkinson catalyst is:

Options
  1. a

    [(Et3P)3IrCl][(\mathrm{Et_3P})_3\mathrm{IrCl}] (Et = C₂H₅)

  2. b

    [(Ph3P)3RhCl][(\mathrm{Ph_3P})_3\mathrm{RhCl}]

  3. c

    [(Ph3P)3IrCl][(\mathrm{Ph_3P})_3\mathrm{IrCl}]

  4. d

    [(Et3P)3RhCl][(\mathrm{Et_3P})_3\mathrm{RhCl}]

Correct Answerb

[(Ph3P)3RhCl][(\mathrm{Ph_3P})_3\mathrm{RhCl}]

Detailed Solution

🧠 Wilkinson's Catalyst — Three Triphenylphosphines and One Rhodium

Wilkinson's catalyst is chlorotris(triphenylphosphine)rhodium(I): [(Ph3P)3RhCl][(\mathrm{Ph_3P})_3\mathrm{RhCl}].

Used for: homogeneous catalytic hydrogenation of alkenes (especially terminal C=C double bonds) under mild conditions.

Two structural cues:

  • Rh (not Ir): Rh(I) is the active centre.
  • PPh₃ (not PEt₃): aryl phosphine, not alkyl.

🗺️ Eliminate Wrong Choices

  • (1) Et₃P + Ir → wrong on both counts.
  • (2) Ph₃P + Rh → Wilkinson's. ✓
  • (3) Ph₃P + Ir → close, but iridium analogue is Vaska's, not Wilkinson's.
  • (4) Et₃P + Rh → wrong phosphine.

The Three Famous Catalysts

| Catalyst | Formula | Use | |---|---|---| | Wilkinson | [(PPh3)3RhCl][(\mathrm{PPh_3})_3\mathrm{RhCl}] | hydrogenation | | Vaska | [(PPh3)2Ir(CO)Cl][(\mathrm{PPh_3})_2\mathrm{Ir(CO)Cl}] | O2\mathrm{O_2} binding studies | | Ziegler-Natta | TiCl4+Et3Al\mathrm{TiCl_4 + Et_3Al} | polyolefin polymerisation | | Grubbs | Ru-carbene + PCy₃ | olefin metathesis |

⚠️ Wilkinson Uses Ph, Vaska Uses Ph — Don't Confuse the Metals

Both use triphenylphosphine. The metal differentiates: Rh = Wilkinson, Ir = Vaska. Memorise the metals, not just the phosphine.

Answer: (2) [(Ph3P)3RhCl]\boxed{\text{Answer: (2) } [(\mathrm{Ph_3P})_3\mathrm{RhCl}]}

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