The compound that has the largest H–M–H bond angle (M = N, O, S, C) is:
Chemical Bonding · Class 11 · JEE Main Previous Year Question
The compound that has the largest H–M–H bond angle (M = N, O, S, C) is:
- a
- b
- c
- d✓
🧠 Lone pairs compress bond angles. More lone pairs → smaller angle. Compare the LP count and hybridisation of each central atom.
| Molecule | Central | Hybridisation | LP | H–M–H angle | |---|---|---|---|---| | | C | sp³ | 0 | 109.5° | | | N | sp³ | 1 | ~107° | | | O | sp³ | 2 | ~104.5° | | | S | ~p (little hybridisation) | 2 | ~92° |
With no lone pairs, achieves the ideal tetrahedral angle. is smallest because S is large and uses nearly unhybridised 3p orbitals (near 90°).
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