The type of hybridization and number of lone pair(s) of electrons of Xe in XeOF4, respectively, are:
Chemical Bonding · Class 11 · JEE Main Previous Year Question
The type of hybridization and number of lone pair(s) of electrons of Xe in , respectively, are:
- a✓
and 1
- b
and 2
- c
and 2
- d
and 1
and 1
🧠 Determine the hybridisation and lone pairs on Xe in .
Xe has 8 valence electrons. In : 4 bonds to F + 1 bond to O = 5 bonds total. LP on Xe = (8 − 5)/2 = 1 lone pair.
Steric number = 5 + 1 = 6 → sp³d² hybridisation → octahedral electron geometry → with 1 LP in one axial position, the molecular shape is square pyramidal.
⚡ Xe uses 3d orbitals to expand beyond the octet: 5 bonds + 1 LP = 12 electrons around Xe, requiring sp³d² hybridisation.
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